I’ve finished the second exercise from Violent Python’s Chapter #1 “The cuckoo’s egg”, it is a password decrypter. Here’s the code:
# # Violent Python Chapter #1 # The Cuckoo's Egg: a simple password decrypter # By: Marin Alcaraz # import crypt import hashlib def testPass(cryptPass): salt = cryptPass[0:2] dictFile = open('dictionary.txt', 'r') for word in dictFile.readlines(): word = word.strip('\n') cryptWord = crypt.crypt(word, salt) if (cryptWord == cryptPass or hashlib.sha512(word) == cryptPass): print "[+] Found Password: " + word + "\n" return print "[-] Password not found.\n" return def main(): passFile = open("passwords.txt", 'r') for line in passFile.readlines(): if ":" in line: user = line.split(':')[0] cryptPass = line.split(':')[1].strip(' ') print "[*] Cracking Password for: user[" + user + "]\n" testPass(cryptPass) return if __name__ == "__main__": main()